Logarithm

The exponential lets us know how much stuffs we will have at a certain growth rate, based on the amount of time that we give it. On the other hand, logarithm lets us know how much time we need to reach a final amount if that amount grows at a certain growth rate.

ex=growthln(growth)=loge(growth)=x=r×te^x = growth \Leftrightarrow \ln(growth) = \log_e(growth) = x = r \times t

Natural Logarithm is the amount of time periods tt necessary to reach a growth value, given that the rate is 100\% and the compound is continuous.

Logarithmic Arithmetic

The arithmetic of logarithm is as follows:

ln(1)=0ln(x)=ln(1x)ln(negative)=undefinedln(ab)=ln(a)+ln(b)ln(a/b)=ln(a)ln(b)\begin{aligned} \ln(1) & = 0 \\ \ln(x) & = - \ln\left(\frac{1}{x}\right) \\ \ln(negative) & = undefined \\ \ln(a*b) & = \ln(a) + \ln(b) \\ \ln(a/b) & = \ln(a) - \ln(b) \end{aligned}

The expression ln(1)\ln(1) is the time it takes to growth from the current value to 1×1 \times the current value. Because we are already there, no time is needed, thus ln(1)=0\ln(1) = 0.

To understand ln(x)=ln(1x)\ln(x) = - \ln\left(\frac{1}{x}\right), we need to see that ln(1x)\ln\left(\frac{1}{x}\right) means the time it takes to grow to the amount to the (1x)\left(\frac{1}{x}\right) of the initial amount. In other words, it is the amount of time taken to shrink or decay an amount by xx. It is the same amount of time, but in different direction. Therefore, intuitively, ln(x)=ln(1x)\ln(x) = - \ln\left(\frac{1}{x}\right)

Because we can never grow our initial positive value to a negative number, there is no such amount of time that we wait will make it happen. Thus ln(negative)=undefined\ln(negative) = undefined

How to understand ln(ab)\ln(a*b)? We can understand via an example. ln(9)\ln(9) is the time taken to grow to 9 times the initial amount. It is equivalent to waiting for the initial amount of grow 3 times, and for that amount to grow 3 more times to reach a factor of 9 in the end. The amount of time waiting for any initial amount to grow 3 times at 100\% rate, continuous compound is ln(3)\ln(3). Thus, ln(9)=ln(33)=ln(3)+ln(3)\ln(9) = \ln(3*3) = \ln(3) + \ln(3). Thus, it means that ln(ab)=ln(a)+ln(b)\ln(a*b) = \ln(a) + \ln(b).

How to understand ln(a/b)\ln(a/b)? Think of it as the time taken for growing by aa minus the time taking to grow to 1b\frac{1}{b} or decay to bb. Remember that growing to bb and decaying to 1/b1/b requires the same amount of time, just in different directions. Thus, ln(a/b)=ln(a)ln(b)\ln(a/b) = \ln(a) - \ln(b).

Mental Math Shortcut: Rule of 72

This rule helps us to calculate quickly the amount of time it takes for an initial amount to double. It states that:

TimeToDouble=72RateInPercentage\begin{aligned} TimeToDouble = \frac{72}{RateInPercentage} \end{aligned}

It is derived based on ln(2)=0.693ln(2) = 0.693, which means that Rate×TimeToDouble=0.693Rate \times TimeToDouble = 0.693, which means TimeToDouble=0.693Rate72RateInPercentageTimeToDouble = \frac{0.693}{Rate} \approx \frac{72}{RateInPercentage}. The number 72 was chosen for being easier for mental calculation.